Home Physics Newton's Laws of Motion First Law of Motion A woman of 50 kg mass is standing in an elev…
Physics Newton's Laws of Motion First Law of Motion MCQ (Single Correct)

A woman of 50 kg mass is standing in an elevator. Suddenly, the cable of the elevator breaks and the elevator begins to fall freely. The force exerted by the floor of the elevator on the woman is -

A
0 kg f
B
50 kg f
C
100 kg f
D
50 × 9.8 kg f

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Text Solution

Verified by Experts
The correct answer is:
A

For a freely falling body apparent weight is zero.

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